1.

2.Show that the diagonals of a rhombus divide it intofour congruent triangles.

Answer»

Let the rhombus be ABCD and let therediameters intersect each other at O.Since,in a Rhombus all sides are equal.

Therefore AB=AD and since ABCD isrhombus therefore its diagonals bisect each other.

So,AO=DOandAO=AO(common)ThereforeΔABO=~ΔADOSimilarly,ΔABO=~ΔBCO

Similarly,ΔBCO=~ΔDCO

Therefore, ΔABO=~ΔBCO=~ΔCDO=~ΔADO



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