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2) Show that image distance changes when object distance changes when object is placed in front of convex lens ? |
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Answer» tion:We are to USE here the Lens maker's for as stated below #1/f=(mu_2/mu_1-1)(1/r_1-1/r_2)# Where f =focal lens of the lens #mu_1=#refractive index of the surrounding medium #mu_2=#refractive index of medium of the lens #r_1=# radius of curvature of the lens of first refracting surface where the beam is incident. #r_2=# radius of curvature of the lens of the second refracting surface through which emergent beam comes out. Here #r_1#and #r_2# remaining same and normally #mu_2> mu_1# If the refractive index of surrounding medium i.e. #mu_1# is increased but kept less than #mu_2# then the ratio #mu_2/ mu_1# will be diminished and as a RESULT the focal length f will be increased. we know #1/v-1/U=1/f# where v = image DISTANCE u = object distance object distance remaining same the image distance proportionately increases with the INCREASE in focal length. |
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