2. Prove that sin 750° cos 480° + cos 120° cos 60° = _1÷2

1.	2. Prove that sin 750° cos 480° + cos 120° cos 60° = _1÷2
Answer» ong>Answer: sin750degree.cos480degree+cos120degree.cos60degree = sin(720 + 30) COS (360 + 120) + cos (180 - 60) cos 60 = sin 30 cos 120 - cos 60 cos 60 = sin 30 cos (180 - 60) - cos^2 60 = -sin30 cos 60 - cos^2 60 = -(1/2)(1/2) - (1/2)^2 = -1/4 - 1/4 = -2/4 = -1/2 Step-by-step explanation: I *hope* *this* *HELP* *you*!!!!!!!!!!

Answer»

ong>Answer:

sin750degree.cos480degree+cos120degree.cos60degree

= sin(720 + 30) COS (360 + 120) + cos (180 - 60) cos 60

= sin 30 cos 120 - cos 60 cos 60

= sin 30 cos (180 - 60) - cos^2 60

= -sin30 cos 60 - cos^2 60

= -(1/2)(1/2) - (1/2)^2

= -1/4 - 1/4

= -2/4

= -1/2

Step-by-step explanation:

I hope this HELP you!!!!!!!!!!

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2. Prove that sin 750° cos 480° + cos 120° cos 60° = _1÷2​

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2. Prove that sin 750° cos 480° + cos 120° cos 60° = _1÷2