2. Prove that a diagnal of a Parallelogram devidesit into two congruen

1.	2. Prove that a diagnal of a Parallelogram devidesit into two congruent triangle
Answer» REQUIRED ANSWER : Given: A PARALLELOGRAM ABCD and AC is its DIAGONAL . To prove : △ABC ≅ △CDA Proof : In △ABC and △CDA, we have ∠DAC = ∠BCA [alt. int. angles, since AD \| \| BC] AC = AC [common side] and ∠BAC = ∠DAC [alt. int. angles, since AB \| \| DC] ∴ By ASA congruence axiom, we have △ABC ≅ △CDA

2. Prove that a diagnal of a Parallelogram devidesit into two congruent triangle

Answer»

REQUIRED ANSWER :

Given: A PARALLELOGRAM ABCD and AC is its DIAGONAL .

To prove : △ABC ≅ △CDA

Proof : In △ABC and △CDA, we have

∠DAC = ∠BCA [alt. int. angles, since AD | | BC]

AC = AC [common side]

and ∠BAC = ∠DAC [alt. int. angles, since AB | | DC]

∴ By ASA congruence axiom, we have

△ABC ≅ △CDA

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2. Prove that a diagnal of a Parallelogram devidesit into two congruent triangle​

REQUIRED ANSWER :

Given: A PARALLELOGRAM ABCD and AC is its DIAGONAL .

To prove : △ABC ≅ △CDA

Proof : In △ABC and △CDA, we have

∠DAC = ∠BCA [alt. int. angles, since AD | | BC]

AC = AC [common side]

and ∠BAC = ∠DAC [alt. int. angles, since AB | | DC]

∴ By ASA congruence axiom, we have

△ABC ≅ △CDA

Discussion

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2. Prove that a diagnal of a Parallelogram devidesit into two congruent triangle