2 \operatorname { sin } 67 \frac { 1 } { 2 } ^ { \circ } \operatorname – InterviewSolution

1.

2 \operatorname { sin } 67 \frac { 1 } { 2 } ^ { \circ } \operatorname { cos } 22 \frac { 1 } { 2 } ^ { \circ } =

Answer»

2sin67.5cos22.5=2sin(90-22.5)cos22.5=2cos22.5cos22.5=1+cos45=1+1/root(2)

thank u

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