2 opandy ulinclos 4ind the ctthe walls

1.	2 opandy ulinclos 4ind the ctthe walls
Answer» Length of a door = 2.5m Breadth of the door = 1.2m area of the door = l * b = 2.5m * 1.2m = 3m^2 ∴ area of 2 doors = 2 * 3 = 6m^2 Length of the window = 1.5m Breadth of the window = 1m Area of the window = l * b = 1.5 * 1 = 1.5m^2 ∴ area of4 windows= 4* 1.5 = 6m^2 Area of the doors + Area of the windows = 6m^2+ 6m^2= 12m^2 Length of the wall = 12.5m Breadth of the wall = 9m Height of the wall = 7m Area of the wall = LSA of a cuboid = 2h(l+b) =2 * 7 (12.5 + 9) = 14 * 21.5 = 301m^2 Required area of the wall to be painted = Area of the wall - Area of the doors and windows i.e., area of the wall to be painted = 301m^2- 12m^2 area of the wall to be painted = 289m^2 Cost of painting 1m^2of the wall = Rs. 3.50 Cost of painting 289m^2of the wall = Rs. (3.50 * 289) Cost of painting the wall = Rs. 1011.5 Like my answer if you find it useful!

Answer»

Length of a door = 2.5m

Breadth of the door = 1.2m

area of the door = l * b = 2.5m * 1.2m = 3m^2

∴ area of 2 doors = 2 * 3 = 6m^2

Length of the window = 1.5m

Breadth of the window = 1m

Area of the window = l * b = 1.5 * 1 = 1.5m^2

∴ area of4 windows= 4* 1.5 = 6m^2

Area of the doors + Area of the windows = 6m^2+ 6m^2= 12m^2

Length of the wall = 12.5m

Breadth of the wall = 9m

Height of the wall = 7m

Area of the wall = LSA of a cuboid = 2h(l+b)

=2 * 7 (12.5 + 9)

= 14 * 21.5 = 301m^2

Required area of the wall to be painted = Area of the wall - Area of the doors and windows

i.e., area of the wall to be painted = 301m^2- 12m^2

area of the wall to be painted = 289m^2

Cost of painting 1m^2of the wall = Rs. 3.50

Cost of painting 289m^2of the wall = Rs. (3.50 * 289)

Cost of painting the wall = Rs. 1011.5

Like my answer if you find it useful!

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