1.

2 n force is applied to an object and it makes displacement 5 m in the direction perpendicular to force. Calculate the work done by the force.​

Answer»

rong>Topic :- Work energy and Power

\maltese\:\underline{\sf AnsWer :} \:  \maltese

  • Force Applied to an object (F) = 2 N
  • DISPLACEMENT of the body (s) = 5 m
  • θ = 90° [∵ Displacement is done in the direction PERPENDICULAR to the Force]

We need to find the work done by the body. To calculate work done by the body we will use the GIVEN below formula :

\longrightarrow\:\sf Work \:  Done = Fs \cos (\theta) \\

Now, simply add the known values from the Question in the above given formula :

\longrightarrow\:\sf Work \:  Done = 2 \times 5 \cos (90^{ \circ} ) \\

\longrightarrow\:\sf Work \:  Done = 10 \cos (90^{ \circ} ) \\

\qquad \qquad\tiny \dag \: \underline{\sf \cos \:  (90^{ \circ}) = 0}

\longrightarrow\:\sf Work \:  Done = 10  \times 0 \\

\longrightarrow\: \underline{ \boxed{\sf Work \:  Done =  0  \: J}}\\

HENCE,the work done by the body is 0 J.



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