2 moles of N_(2)H_(4) loses 16 moles of electrons is being converted to a new compound x. Assuming that all of the N appears in the new compound, what is the oxidation state of N in x?

2 moles of N_(2)H_(4) loses 16 moles of electrons is being converted t

1.	2 moles of N_(2)H_(4) loses 16 moles of electrons is being converted to a new compound x. Assuming that all of the N appears in the new compound, what is the oxidation state of N in x?
Answer» `-1` `-2` `+2` `+4` SOLUTION :`2N_(2)H_(4)rarrX+16e^(-)` `1N_(2)H_(4)rarr8e^(-)` i.e., n-factor = 8 = (`Delta` ox. No.) `xx2` implies `Delta` ox. No. = 4 Ox. No in `N_(2)H_(4)=-2` implies Final ox. No. `=-2+4=+2`