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2 moles of gas contained in a four litre flask exerts a pressure of Il atm at 27^@C. If vander Waals parameter bis 0.05 l/mol, the value of 'a' (in atm "lt"^(2) "mol"^(-2)) is |
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Answer» 6.46 `(P + (an^2)/(V^2)) (V - nb) = nRT` `(11 + (a XX 4)/(10)) (4 - 2 xx 0.05) = 2 xx 0.0821 xx 300` `= 11 + a/4 = 12.6 implies a = 6.4`. |
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