1.

2 moles each of liquid a and b ate dissolved to form an ideal somution. What will be the mole fraction of b in vapoir state

Answer»

ANSWER:

We know that, mole fraction can be calculated USING the following formula:

P_{<klux>B</klux>} =P_{T} *X_{B}

Here P_{B} is partial pressure of B=100 mm Hg as in the vapor phase the partial pressure of B will be EQUAL to its vapor pressure in pure state.

And P_{T}=(100+200)mm of Hg

so we get

X_{B} =P_{B} /P_{T}

=200/300

=2/3



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