1.

2 "mole" of PCl_(5) were heated in a closed vessel of 2 litre capacity. At equilibrium 40% of PCl_(5) dissociated into PCl_(3) and Cl_(2). The value of the equilibrium constant is:

Answer»

`0.266`
`0.53`
`2.66`
`5.3`

Solution :`underset(2)(PCl_(5))hArrunderset(0)(PCl_(3))+underset(0)(Cl_(2))`
`(2xx60)/(100)(2xx40)/(100)(2xx40)/(100)`
Volume of CONTAINER =2 litre.
`K_(c)=((2xx40)/(100xx2)xx(2xx40)/(100xx2))/((2xx60)/(100xx2))=0.266.`


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