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2 mole, equimolar mixture of Na_(2)C_(2)O_(4) and H_(2)C_(2)O_(4)required V_1 Lof 0.1 M KMnO_4in acidic medium for complete oxidatiion. The same amount of the mixture required V_2 L of 0.1 M NaOH for neutralization. The ratio of V_(1) "to "V_2is x:y, then the value of x + y is (x and y are integers)

Answer»

Solution :No.of MOLES of `Na_2C_2O_4 =H_(2)C_(2)O_(4)=1`
`4 =v_1 xx0.5 , v_1 =8L`
`2 =v_2 xx0.1 impliesv_(2)=20L`
`v_1:v_2=8:20`
`= 2:5 =x:y , x +y=7`


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