2 men and 5 chilren can finish 1/2 portion of work in 5 days while 3 m

1.	2 men and 5 chilren can finish 1/2 portion of work in 5 days while 3 men and 4 children can finish 1/3 portion of it in 3 days. How many days will 9 men take to entire work
Answer» ANSWER: Step-by-step explanation: 2 men and 5 children can FINISH 1/2 portion of the work in 5 days, means that 2 men and 5 children can finish the whole work in 10 days. 3 men and 4 children can finish 1/3 portion of the work in 3 days, means that 3 men and 4 children can finish the whole work in 9 days. The work requires 20 man-days and 50 child-days or 27 man-days and 36 child-days. Or 20 md+ 50 cd = 27 md + 36 cd, or 50 cd - 36 cd = 14 cd = 27 md - 20 md = 7 md. Or 1 man is equal to 2 children. Thus the whole work requires 20 man-days + 50 child-days-man/2children = 20 + 25 = 45 man-days.

2 men and 5 chilren can finish 1/2 portion of work in 5 days while 3 men and 4 children can finish 1/3 portion of it in 3 days. How many days will 9 men take to entire work

Answer»

ANSWER:

Step-by-step explanation:

2 men and 5 children can FINISH 1/2 portion of the work in 5 days, means that

2 men and 5 children can finish the whole work in 10 days.

3 men and 4 children can finish 1/3 portion of the work in 3 days, means that

3 men and 4 children can finish the whole work in 9 days.

The work requires 20 man-days and 50 child-days or

27 man-days and 36 child-days.

Or 20 md+ 50 cd = 27 md + 36 cd, or

50 cd - 36 cd = 14 cd = 27 md - 20 md = 7 md. Or 1 man is equal to 2 children.

Thus the whole work requires 20 man-days + 50 child-days-man/2children

= 20 + 25 = 45 man-days.

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