2 litres of nitrogen completely react with 6 litres of hydrogen under suitable conditions to form 4 litres of NH_3. If all the volumes are measured at the same temperature and pressure, show that the data given are in accordance to the Gay Lussac's law of combining volumes.

2 litres of nitrogen completely react with 6 litres of hydrogen under

1.	2 litres of nitrogen completely react with 6 litres of hydrogen under suitable conditions to form 4 litres of NH_3. If all the volumes are measured at the same temperature and pressure, show that the data given are in accordance to the Gay Lussac's law of combining volumes.
Answer» Solution :The reaction mentioned in the question takes place as follows : `underset("2 litres")((N_(2)(g)) +underset("6 litres")(3H_(2)(g)) to underset("4 litres")(2NH_(3)(g))` The volumes of the reacting gases are in the ratio 2 : 6, i.e., 1: 3. The product ammonia is ALSO a gas and its VOLUME also bears a simple whole number ratio with the volumes of reactants. The ratio of the volumes of all reactants and product in this reaction is thus 1:3:2 Since, the ratio is a simple whole number ratio, the data are in ACCORDANCE to the Gay Lussac.s law of combining volumes.