1.

2 KG of water at 352 K is mixed with 2 KG of water at 302 K. Kept in a container what is the resultant temperature of this mixture?

Answer»

ined by COLD body =heat lost by hot bodyQ=Heat energym=mass of waterc=Specific heat capacityHeat lostfor convenience convert TEMP in Kelvin to celcius by SUBTRACTING by 273t=final tempt2=INITIAL tempQ1=mc(t2-t1)  =2 *4200*(79-t)heat gainedt=final tempt1= initial tempQ2=mc(t-t1)=2*4200(t-49)Q1=Q22*4200(79-t)=2*4200(t-49)79-t=t-492t=128t=64



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