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2 kg ice at -20 degree celsius is mixed with 5 kg water at 20 degree celsius. Then final amount of water in the mixture would be; Given specific heat of ice = 0.5 cal/g degree celsius, Specific heat of water = 1 cal/g degree celsius (1) 6 kg (2) 5 kg (3) 4 kg (4) 2 kg |
| Answer» 2 kg ice at -20 degree celsius is mixed with 5 kg water at 20 degree celsius. Then final amount of water in the mixture would be; Given specific heat of ice = 0.5 cal/g degree celsius, Specific heat of water = 1 cal/g degree celsius (1) 6 kg (2) 5 kg (3) 4 kg (4) 2 kg | |