(2) Kantabai bought 1 kg tea and 5 kg sugar from a shop. She paid ?50

1.	(2) Kantabai bought 1 kg tea and 5 kg sugar from a shop. She paid ?50 asreturn fare for rickshaw. Total expense was ? 700. Then she realised that byordering online the goods can be bought with free home delivery at the sameprice. So next month she placed the order online for 2 kg tea and 7 kg sugar.She paid 880 for that. Find the rate of sugar and tea per kg
Answer» Let price of 1 kg tea = xLet price of 1 kg sugar = y 3/2x + 5y + 50 = 7003x + 10y = 1300.....(1)2x + 7y = 880......... (2) Multiply eq(1) by 2 and eq(2) by 3 6x + 20y = 2600......(3)6x + 21y = 2640......(4) Subtract eq(3) from eq(4)y = 40 Put value of y = 40 in eq(1)3x + 10*40 = 13003x = 1300 - 4003x = 900x = 300 Price of 1 kg tea = Rs 300Price of 1 kg sugar = Rs 40 let price of 1 kg tea = xlet price of 1 kg sugar =y 3/2+5y+50=7003x+10y= 1300....(1) 2x+7y= 880......(2) Multiply eqn (1) by 2 & eqn (2)

(2) Kantabai bought 1 kg tea and 5 kg sugar from a shop. She paid ?50 asreturn fare for rickshaw. Total expense was ? 700. Then she realised that byordering online the goods can be bought with free home delivery at the sameprice. So next month she placed the order online for 2 kg tea and 7 kg sugar.She paid 880 for that. Find the rate of sugar and tea per kg

Answer»

Let price of 1 kg tea = xLet price of 1 kg sugar = y

3/2x + 5y + 50 = 7003x + 10y = 1300.....(1)2x + 7y = 880......... (2)

Multiply eq(1) by 2 and eq(2) by 3

6x + 20y = 2600......(3)6x + 21y = 2640......(4)

Subtract eq(3) from eq(4)y = 40

Put value of y = 40 in eq(1)3x + 10*40 = 13003x = 1300 - 4003x = 900x = 300

Price of 1 kg tea = Rs 300Price of 1 kg sugar = Rs 40

let price of 1 kg tea = xlet price of 1 kg sugar =y

3/2+5y+50=7003x+10y= 1300....(1) 2x+7y= 880......(2)

Multiply eqn (1) by 2 & eqn (2)