1.

(2) InABC, A-P-B and A-Q-C such thatseg PQ İ side BC and seg PQ divides Δ ABC in twoBPparts whose areas are equal. Find the value of AB

Answer»

Given : PQ is parallel to BC and PQ divides triangle ABC into two parts.To find : BP/AB

Proof : InΔ APQΔ ABC,

∠ APQ =∠ ABC (As PQ is parallel to BC)

∠ PAQ =∠ BAC (Common angles)

⇒Δ APQ ~Δ ABC (BY AA similarity)

Therefore,

ar(Δ APQ)/ar(Δ ABC) = AP²/AB²

⇒ ar(Δ APQ)/2ar(Δ APQ) = AP²/AB²

⇒ 1/2 = AP²/AB²

⇒ AP/AB = 1/√2

⇒ (AB - BP)/AB = 1/√2

⇒ AB/AB - BP/AB = 1/√2

⇒ 1 - BP/AB = 1/√2

⇒ BP/AB = 1 - 1/√2

⇒ BP/AB =√2 - 1/√2



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