1.

2. In the given figure, ABCD is a square andDCE is an equilateral triangle. Prove that:(i) ADE = BCE(ii) AE = BE​

Answer»

Step-by-step explanation:

Given, ABCD is a square. DCE is an EQUILATERAL TRIANGLE.

ABCD is a square,

AB=BC=CD=DA

DCE is an equilateral triangle,

DC=DC=CE

Hence, AB=BC=CD=DA=CE=DC

Now, In △ADE,

AD=DE

Thus, ∠AED=∠DAE=x

∠ADE=∠ADC+∠EDC

∠ADE=90+60

∠ADE=150

∘

Sum of angles of triangle ADE = 180

∠ADE+∠AED+∠DAE=180

150+x+x=180

x=15

∘

Hence, ∠DAE=15

∘


Discussion

No Comment Found

Related InterviewSolutions