2. In the figure showna particle of mass m is tied to a string and the

1.	2. In the figure showna particle of mass m is tied to a string and the other end ofe side wall of a carriage, which is accelerating horizontally withstring is tied to thconstant acceleration a. Assuming the string remains taut and the particle is noin contact with the base of carriage. Then : (Particle is at rest with respect tocarriage)畜" (a)A) The angle θ that string makes with the horizontal is tan--1(B) The angle θ that string makes with the horizontal is tan(C) Tension in the string is mVg2+a(D) Tension in the string is my/g -aa clides down the smooth face PR of a wedge A of
Answer» Forces acting on the mass are mg in downward direction and pseudo force in backward direction of the acceleration. = ma. so the angle ∅ is tan⁻¹(g/a) and the value of tension is net force on it that is √(mg² +ma²) = m√(g²+a²) option a and c are correct.

2. In the figure showna particle of mass m is tied to a string and the other end ofe side wall of a carriage, which is accelerating horizontally withstring is tied to thconstant acceleration a. Assuming the string remains taut and the particle is noin contact with the base of carriage. Then : (Particle is at rest with respect tocarriage)畜" (a)A) The angle θ that string makes with the horizontal is tan--1(B) The angle θ that string makes with the horizontal is tan(C) Tension in the string is mVg2+a(D) Tension in the string is my/g -aa clides down the smooth face PR of a wedge A of

Answer»

Forces acting on the mass are mg in downward direction and pseudo force in backward direction of the acceleration. = ma.

so the angle ∅ is tan⁻¹(g/a)

and the value of tension is net force on it that is √(mg² +ma²) = m√(g²+a²)

option a and c are correct.

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