Saved Bookmarks
| 1. |
2. In fig AB and CDintersect each otherE such that DEBEand EA = ECShow that AD CB |
|
Answer» In ∆ADE & ∆BCE,AE=CEDE=BEangle AED= angle BECBY SAS CRITERION,∆ADE congruent ∆BCEBY CPCT, AD=BCHENCE PROVED in ΔAED andΔBECDE=BE(given)EA=EC(given)ang(AED)=ang(BEC)[vert.opps angls]therefore by SAS congruenceΔAED≈ΔBECsoEA=EC(Cpct) |
|