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2. In fig AB and CDintersect each otherE such that DEBEand EA = ECShow that AD CB

Answer»

In ∆ADE & ∆BCE,AE=CEDE=BEangle AED= angle BECBY SAS CRITERION,∆ADE congruent ∆BCEBY CPCT, AD=BCHENCE PROVED

in ΔAED andΔBECDE=BE(given)EA=EC(given)ang(AED)=ang(BEC)[vert.opps angls]therefore by SAS congruenceΔAED≈ΔBECsoEA=EC(Cpct)



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