2. Heat of formation of benzene, assuming no resonance. Given thatBE (C-C) = 83 kcalBE (C=C) = 140 kcalBE (C-H) = 99 kcalHeat of atomisation of C = 170.9 kcalHeat of atomisation of H = 104.2 kcalwill be(1) 39 kcal(2) 75 kcal(3) 1263 kcal(4) 421 kcal

2. Heat of formation of benzene, assuming no resonance. Given thatBE

1.	2. Heat of formation of benzene, assuming no resonance. Given thatBE (C-C) = 83 kcalBE (C=C) = 140 kcalBE (C-H) = 99 kcalHeat of atomisation of C = 170.9 kcalHeat of atomisation of H = 104.2 kcalwill be(1) 39 kcal(2) 75 kcal(3) 1263 kcal(4) 421 kcal
Answer» first find TOTAL HEAT of FORMATION of PRODUCT then total heat of formation of reactant heat of formation = heat of reactant -heat of product