2) Five year ago , a father was seven times as old as his son. Five ye

1.	2) Five year ago , a father was seven times as old as his son. Five years hence, the fatherwill be three times as old as his son. Find their present ages.
Answer» Answer: LET present age of SON be x FIVE YEARS ago, sons age = x-5 FATHER's age=7(x-5) five years hence, son's age =x+5 father's age=3( x+5) Step-by-step explanation: 7x-35=3x+15 4x=50 x=12.5

2) Five year ago , a father was seven times as old as his son. Five years hence, the fatherwill be three times as old as his son. Find their present ages.

Answer»

Answer:

LET present age of SON be x

sons age = x-5

FATHER's age=7(x-5)

five years hence,

son's age =x+5

father's age=3( x+5)

Step-by-step explanation:

7x-35=3x+15

4x=50

x=12.5