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2. Find the zeros and number of zeros of p(x) = x2 + 9x + 18. Show them on a graph. |
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Answer» x=-b+-√b^2-4ac/2ax=-9+-√81-4*1*18/2*1X=-9+-√9/2X=-9+3/2=-6/2=-3X=-9-3/2=-12/2=-6 Thanks |
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