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2.Find the value of K, for which one root of the quadratic equation kx2-14x+8 = 062. |
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Answer» Given : p(x) = kx² - 14x + 8 = 0 As 2 is root p(2) = 0 2²k - 28 + 8 = 0 4k = 20 k = 5 |
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