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2. Find the roots of the quadratic equation 3x2-2x-./Đ-Đ. |
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Answer» √3x² - 2x - √3 = 0 √3x² - 3x + x - √3 = 0 √3x ( x - √3) + ( x - √3) = 0 ( √3x + 1) ( x - √3) = 0 So, x = -1/√3 and √3 |
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