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(2) Find the quadratic equation whose roots are the reciprocals of the rootsof + 4x - 10 = 0.et c.&B be the |
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Answer» x=-5, x=-1 is the best answer x^2+4x-10=0as per shridhar acharyax= -b+-√b^2-4ac/2ahere a= 1, b= 4, c= -10x= -4+-√(4)^2-4×1(-10)/2×1 = -4+-√16+40/2 = -4+-√56/2 = -4+-2√14/2 = 2(√14-2)/2= +-(√14-2)roots are (√14-2) & (2-√14)reciprocal of root =1/√14-2 & 1/2-√14sum of root= 1/√14-2 + -(1/√14+2)= √14+2-√14+2/(√14)^2-(2)^2=4/14-4=4/10=2/5product of root= (1/√14+2){-(1/√14+2)=-{1/(√14)^2-(2)^2= -1/14-4= -1/10eq=x^2-x(sum of root)+(product of root)=0x^2-x{2/5)+(-1/10)=010x^2-4x-1=0 X=-5. X=1 is the answer of this question |
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