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।2"]( डी १ )15: 1 आह31o| \| | \(&N ’;‘—\’ |
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Answer» We know sinθ.sin(60 - θ).sin(60 + θ) = ¼sin3θ So, sin12.sin48.sin54.sin72/sin72 = ¼sin36.sin54/sin72 = ¼sin36.cos36/sin72 = ⅛sin72/sin72 = ⅛ |
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