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2 circles of radii 5cm and 3cm are concentric. calculate the length of a chord of the outer circle which touches the inner |
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Answer» Answer: Let the RADIUS of the bigger circle be 'R' and the radius of the SMALLER circle be 'r'. It is given that R=5cm=OB and r=3cm=OD and AB is the chord whose length we have to find. AD=BD and OD⊥AB(radius is perpendicular to a chord and it DIVIDES the chord into two equal parts) therefore, ΔODB is a right angled triangle where, OD²+BD²=OB² (3)²+BD²=(5)² 9+BD²=25 BD²=25-9 BD²=16 BD=4cm Since AD=BD=4cm therefore, AB=AD+BD AB=4+4 AB=8cm Read more on Brainly.in - brainly.in/question/1686191#readmore Step-by-step EXPLANATION: |
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