1.

2-Bromopentane is treated with alcoholic KOH solution. Whatt will be the major product formed in this reaction and what is the type of elimination called?

Answer»

Pent-1-ene, `beta`-Elimination<BR>Pent-2-ene, `beta`-elimination
Pent-1-ene, Nucleophilic substitution
Pent-2-ene, Nucleophilic substitution.

Solution :`underset("2-Bromopentane")(CH_(3)CH_(2)-CH_(2)-) underset(Br)underset(|)(C)H-CH_(3) underset(-HBR" "(beta-"elimination"))overset("alc. KOH")to CH_(3)-underset("2-Pentene")(CH_(2)-CH=CH-CH_(3))`.


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