2. Atato be such thnt whro142. meter tto be 3tower theneANăŹ3

1.	2. Atato be such thnt whro142. meter tto be 3tower theneANăŹ3
Answer» First case:-tanx=5/12 = height of tower /distance (d) ---------------(1) second case:-3/4 = height of tower /(d-192)-------(2) from equation (1) and (2) 3 (d-192)/4=5d/12 9 (d-192)=5d9d - 1728=5d 4d=1728d=432 m nowheight of tower =5 x 432/12 =5 x 36=180 m Like my answer if you find it useful!

Answer»

First case:-tanx=5/12 = height of tower /distance (d) ---------------(1)

second case:-3/4 = height of tower /(d-192)-------(2)

from equation (1) and (2)

3 (d-192)/4=5d/12 9 (d-192)=5d9d - 1728=5d 4d=1728d=432 m

nowheight of tower =5 x 432/12 =5 x 36=180 m

Like my answer if you find it useful!

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