2. Adjacent sides of a rectangle are 7 cm and 24 cmagonal.

1.	2. Adjacent sides of a rectangle are 7 cm and 24 cmagonal.
Answer» In the given figure, ABCD is a rectangle with length 24 cm and breadth 7 cm. Also, in the figure, BCD is a triangle right angled at D. CD = Base = B = 24 cmBD = Perpendicular = P = 7 cmBC = Hypotenuse = H = H So, according to Pythagoras Theorem, Hypotenuse^2 = Base^2 + Perpendicular^2 (H)^2 = (B)^2 + (P)^2 => (H)^2 = (24)^2 + (7)^2 => (H)^2 = 576 + 49 => (H)^2 = 625 => H = √(625) => H = 25 cm Diagonal = Hypotenuse = 25 cm

Answer»

In the given figure, ABCD is a rectangle with length 24 cm and breadth 7 cm.

Also, in the figure, BCD is a triangle right angled at D.

CD = Base = B = 24 cmBD = Perpendicular = P = 7 cmBC = Hypotenuse = H = H

So, according to Pythagoras Theorem,

Hypotenuse^2 = Base^2 + Perpendicular^2

(H)^2 = (B)^2 + (P)^2

=> (H)^2 = (24)^2 + (7)^2

=> (H)^2 = 576 + 49

=> (H)^2 = 625

=> H = √(625)

=> H = 25 cm

Diagonal = Hypotenuse = 25 cm

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