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2. A wire of length L, m is redrawn to a length2L m, then the resistance will(a) increase two times(b) not charge(c) decrease to 1/4 of the original(d) increase four times. |
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Answer» As we know that ;Resistance = Resistivity*length/areaHere we note that the resistance is directly proportional to length and inversely proportional to area of cross section ....Now a/c to question,;Length of wire is double then area is reduced to half...NowNew resistance = resistivity*2length/area/2New resistance =(resistivity*length/area)*4New resistance = 4resistanceOption (4) is correct. |
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