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2. A stone is dropped from the top of a tower and allowed to travel freely under gravity. What is the initial velocity of the stone?​

Answer»

Given, a=g=10m/s 2 t=4su=0m/s {INITIAL VELOCITY at rest}So, height= ut+ 21 at 2 =(0)(u)+ 21 (10)(16)=80m∴ Height of the tower= 80m



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