Saved Bookmarks
| 1. |
2. A rectangular tank measuring 5 m × 4.5 m × 2.1 m is dug in the centre of the field measuring 13.5 m × 12.5 m. The earth dug out is spread evenly over the remaining portion of the field. How much is the level of the field raised? |
|
Answer» Step-by-step EXPLANATION: Area of field=13:5×2:5=33:75 Upper area of tank=5×4:5=22:5 Area of field on which SOIL is spread=33:75_22:5 =11:25m Volume of tank=5×4:5×2:1=47:25m^3 RAISED in level=volume of tank/area of field on which soil spread=47:25/11:25=4:2 So,raised level=4:2m |
|