1.

2. A rectangle has a perimeter measuring 64 cm. The length is 4 cmmore than 3 times the breadth. Find the dimensions of therectangle.​

Answer»

ANSWER :

Dimensions are 25 cm and 7 cm.

EXPLANATION :

GIVEN :-

  • Perimeter of rectangle is 64 cm.
  • The length is 4cm more than 3 times the breadth.

TO FIND :

  • Dimensions of the rectangle.

SOLUTION :

Let the breadth of the rectangle be x cm.

Length is 4 cm more than 3 times the breadth.

Length = (3x + 4) cm

We know,

{\boxed{\sf{Perimeter\:of\: rectangle=2(Length+Breadth)}}}

Perimeter = 2(3x+4+x) cm

→ Perimeter = 2(4x+4) cm

Perimeter = 8(x+1) cm

According to the QUESTION,

\sf{\:\:\:\:\:8(x+1)=64}

\implies\sf{x+1=\frac{64}{8}}

\implies\sf{x+1=8}

\implies\sf{x=8-1}

\implies\sf{x=7}

Breadth = 7 cm.

Length = (3 × 7 + 4 ) cm

Length = 25 cm

Therefore ,dimensions are 25 cm and 7 cm.

_____________________

VERIFICATION :

Length of rectangle = 25 cm.

Breadth of rectangle = 7 cm.

Perimeter of rectangle=2(25+7) cm

→ Perimeter of rectangle= 64 cm.

Hence verified___!!

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