1.

(2) A line passes through the points A (-1, 1) and B (2, 2). Without using graph, siareason, through which quadrants the line passes.​

Answer»

Step-by-step explanation:

The equation of line is y=\frac{1}{3}(x)+\frac{4}{3}. The line passing through first, second and THIRD quadrant.

Step-by-step explanation:

It is given that the line is passing through the POINTS A(-1,1) and B(2,2).

If a line passing through the two points, then the equation of line is

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

The equation of line AB is

y-1=\frac{2-1}{2-(-1)}(x-(-1))

y-1=\frac{1}{3}(x+1)

y=\frac{1}{3}(x)+\frac{1}{3}+1

y=\frac{1}{3}(x)+\frac{4}{3}

Using slope intercept FORM we can say that the slope of the line is \frac{1}{3} and y-intercept is \frac{4}{3}.

Put y=0, to find the x-intercept.

0=\frac{1}{3}(x)+\frac{4}{3}

-\frac{4}{3}=\frac{1}{3}(x)

x=-4

Since the x-intercept is negative, y-intercept is positive and slope is positive, therefore the line passing through first, second and third quadrant.


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