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2. A can do a piece of work in 40 days; B can do the same in 30 days. A started alone but left the work after 10 days, then Bworked at it for 10 days. C finished the remaining work in 10 days. Calone can do the whole work in?A. 24 days B. 30 days C. 44 days D. 17 1/2 days3. A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they cando it in:A.20 days B.22 days C.25 days D.30 days E. None of these4. If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the timetaken by 15 men and 20 boys in doing the same type of work will be:1.7 daysleft the job. In how manyUs |
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Answer» 2a.24days 3b.22whole1\2 4.c. 4days Step-by-step explanation: 2.Let the total WORK be x UNITS. A can do the work in 40 days. 1 day work of A = x/40 B can do the work in 30 days. 1 day work of B = x/30 = For the first 10 days A does the work alone. 10 ays work of A = 10 x x/40 = x/4 For the next 10 days B does the work alone. 10 days work of B = x/3C does the remaining work left in the last 10 days . x = 10 days work of C + x/3 + x/4 => 10 days work of C = 5 x/12 C can do 5x/12 units of work in 10 days. C can do x units of work in = (x x 10)/(5x/ 12) = 24 days 3.Ratio of times taken by A and B =1:3 The time difference is (3−1)2 days while B takes 3 days and A takes 1 day. If difference of time is 2 days, B takes 3 days. If difference of time is 60 days, B takes ( 2 3
×60)=90 days. So, A takes 30 days to do the work. A's 1 day's work = 30 1
B's 1 day's work = 90 1
(A+B)'s 1 day's work =( 30 1
+ 90 1
)= 90 4
= 45 2
∴ A and B can do the work in 2 45
=22 2 1
days. 4.Given that 6 men and 8 boys can do a piece of work in 10 days 26 men and 48 boys can do the same in 2 days
As the work done is equal, 10(6M + 8B) = 2(26M + 48B) 60M + 80B = 52M + 96B => M = 2B => B = M/2 ……(1)
Now Put (1) in 15M + 20B => 15M + 10M = 25M Now, 6M + 8B in 10 days => (6M + 4M) 10 = 100M Then D(25M) = 100M => D = 4 days. |
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