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2.A(-5, 2) and B(4, 1). Find the equation ofthe locus of point P, which is equidistantfrom A and B. |
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Answer» Step-by-step explanation: AP = BP AP² = BP² (x+5)² + (y-2)² = (x-4)² + (y-1)² x² + 25 + 10x + y² + 4 - 4Y = x² + 16 - 8x + y² +1 - 2y 18x - 2y + 12 = 0 so , locus of P is a straight line PLEASE MARK AS BRAINIEST |
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