2.82g of glucose molar mass 180 are dissolved in 30g of water calculat

1.	2.82g of glucose molar mass 180 are dissolved in 30g of water calculate the Molarity
Answer» Answer: 0.52 M Explanation: Moles of GLUCOSE dissolved n = 2.82 G / (180 g/mol) n = (47/3000) mol Volume of 30 g water V = Mass / Density V = 30 g / (1 g/ml) V = 30 ml V = 30 × 10^(-3) Litres Molarity = Moles of SOLUTE / Litres of solution = (47/3000 mol) / (30 × 10^-3 L) = 47/90 M = 0.52 M

2.82g of glucose molar mass 180 are dissolved in 30g of water calculate the Molarity

Answer»

Answer:

0.52 M

Explanation:

Moles of GLUCOSE dissolved

Volume of 30 g water

Molarity = Moles of SOLUTE / Litres of solution

= (47/3000 mol) / (30 × 10^-3 L)

= 47/90 M

= 0.52 M