-2*60^circ*cosec^2 %2B 3*cos(30^circ)^2 %2B (4/3)*tan(60^circ)^2 - 3*c – InterviewSolution

1.

-260^circcosec^2 %2B 3cos(30^circ)^2 %2B (4/3)tan(60^circ)^2 - 3*cot(45^circ)^2/4

Answer»

4/3 (V3)^2+3(V3/2)^2-2(2/V3)-3/4(1)=4/3(3)+3(3/4)-4/3-3/4=4+9/4-4/3-4/3=10

10 is the correct answer of the given question

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