(2/3)*(-sin(45^circ)^4 %2B cos(30^circ)^4) - 3*(sin(60^circ)^2 - sec(4 – InterviewSolution

1.

(2/3)(-sin(45^circ)^4 %2B cos(30^circ)^4) - 3(sin(60^circ)^2 - sec(45^circ)^2) %2B cot(30^circ)^2/4

Answer»

trigonometry values yaad karo aur solve karo

2/3 ((V3/2)^4-(1/V2)4)-((sin^2V3/2)-(2)^2)+1/4(V3)2= 2/3(9/16)-1/4)-(3/4-4)+1/4(3)=3/4-1/4- 3/4-4+3/4=1/4

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