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(2/3)*(58^circ*cosec^2) - 2*tan(32^circ)*cot(58^circ)/3 - 5*tan(13^circ)*tan(37^circ)/3 |
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Answer» {2/3 cosec^2 (58)} - {2/3 (cot 58)( tan 32)} - {5/3 (tan 13)( tan 37 )( tan 45 )( tan 53 )( tan 77)}] Using: tan x = cot (90 - x) ={[2/3 cosec^2 58} -{2/3 cot^2 58} - {5/3 (tan 13 tan 37 tan 45 cot 37 cot 13}] =2/3(cosec^2 58 - cot^2 58) - 5/3 [since, tan 45 = 1] =2/3 -5/3 [Using cosec^2 x - cot^2 x = 1] = -1 |
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