√2+√3÷3√2-2√3=a-b√6Factorise

1.	√2+√3÷3√2-2√3=a-b√6Factorise
Answer» Question: $= > \frac{ \sqrt{2} + \sqrt{3} }{3 \sqrt{2} - 2 \sqrt{3} } = a - b \sqrt{6}$ ANSWER: $= > \frac{ \sqrt{2} + \sqrt{3} }{3 \sqrt{2} - 2 \sqrt{3} } = a - b \sqrt{6}$ RATIONALISING L.H.S., $= > \frac{( \sqrt{2} + \sqrt{3} )(3 \sqrt{2} + 2 \sqrt{3} ) }{18 - 12} = a - b \sqrt{6}$ $= > \frac{6 + 2 \sqrt{6} + 3 \sqrt{6} + 6 }{6} = a - b \sqrt{6}$ $= > 12 + 5 \sqrt{6} = 6a - 6b \sqrt{6}$ On COMPARING both sides, $= > 6a = 12$ $= > a = 2$ $= > - 6b = 5$ $= > b = \frac{ - 5}{6}$ Hope this answer HELPS you ^_^ !

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