2) 10*AT36/Cakulate the total number of electrons flowing through a ci

1.	2) 10*AT36/Cakulate the total number of electrons flowing through a circuit in 20 min and 40 sec. Incurrent of 40 u A flows through the circuit (HW)1) 31 x 102) 31 x 103)31 x 10144)31 x 1015you
Answer» Answer: OPTION A IS THE CORRECT ANSWER. PLZ MARK ME AS BRAINLIEST ANSWER.

2) 10*AT36/Cakulate the total number of electrons flowing through a circuit in 20 min and 40 sec. Incurrent of 40 u A flows through the circuit (HW)1) 31 x 102) 31 x 103)31 x 10144)31 x 1015you

Answer»

Answer:

OPTION A IS THE CORRECT ANSWER. PLZ MARK ME AS BRAINLIEST ANSWER.

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2) 10*AT36/Cakulate the total number of electrons flowing through a circuit in 20 min and 40 sec. Incurrent of 40 u A flows through the circuit (HW)1) 31 x 102) 31 x 103)31 x 10144)31 x 1015you​

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2) 10*AT36/Cakulate the total number of electrons flowing through a circuit in 20 min and 40 sec. Incurrent of 40 u A flows through the circuit (HW)1) 31 x 102) 31 x 103)31 x 10144)31 x 1015you