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2*10^7 electrons are flowing through a conductor in 2 milliseconds how much current will flow?

Answer»

1.6*10^-9AExplanation:CURRENT I =Q/t=ne/tn=2*10^7 electronse=1.6*10^-19t=2*10^-3I=(2*10^7)(1.6*10^-19)/2*10^-3=1.6*10^-9 A



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