1.

∫ 1sin(x-a) sin (x-b)dx is equal to (a) sin b-a logsin(x-a)sin(x-b)+C (b) cosec b-a logsin(x-a)sin(x-b)+C(c) cosec b-a logsin(x-b)sin(x-a)+C (d) sin b-a logsin(x-a)sin(x-b)+C

Answer» 1sin(x-a) sin (x-b)dx is equal to (a) sin b-a logsin(x-a)sin(x-b)+C (b) cosec b-a logsin(x-a)sin(x-b)+C(c) cosec b-a logsin(x-b)sin(x-a)+C (d) sin b-a logsin(x-a)sin(x-b)+C


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