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| 1. |
`1g` pure iron is dissolved in excess of `H_(2)SO_(4)`. The clear filtrate is made up `100 mL. 10mL` of this solution is treated with `0.1 M KMnO_(4)` solution till whole of the `Fe^(2+)` ions are oxidised to `Fe^(3+)` ions. Now `0.2 g Fe_(2)(SO_(4))_(3)` is dissolved in it. the solution is now treated with `Zn` and `H_(2)SO_(4)`. The ratio of equivalent of `KMnO_(4)` and `K_(2)Cr_(2)O_(7)` used for reducing the solution is:A. `5//6`B. `6//5`C. `1`D. `2` |
| Answer» Eq. of `KMnO_(4)`=Eq. of `K_(2)Cr_(2)O_(7)`=Eq. of `Fe^(2+)` | |