Saved Bookmarks
| 1. |
`1g` pure iron is dissolved in excess of `H_(2)SO_(4)`. The clear filtrate is made up `100 mL. 10mL` of this solution is treated with `0.1 M KMnO_(4)` solution till whole of the `Fe^(2+)` ions are oxidised to `Fe^(3+)` ions. Now `0.2 g Fe_(2)(SO_(4))_(3)` is dissolved in it. the solution is now treated with `Zn` and `H_(2)SO_(4)`. Select the correct statement. `1.` The `Fe^(3+)` ions present in solution are reduced by `Zn` and `H_(2)SO_(4)` `2. H_(2)` gas formed by the action of `Zn` and `H_(2)SO_(4)` is reducing agent. `3.` Atomic form of `H` formed by the action of `Zn` and `H_(2)SO_(4)` is reducing agent `4.` Nascent form of `H` formed by the action of `Zn` and `H_(2)SO_(4)` is reducing agentA. `1,2`B. `1,3`C. `1,4`D. `1,2,3` |
|
Answer» `Zn+H_(2)SO_(4)toZnSO_(4)+underset("Nascent H")(2H)` `Fe^(3+)+HtoFe^(2+)+H^(+)` |
|