1g of mg is burnt in a closed vessel contatining 0.5gvof Oxygen what i

1.	1g of mg is burnt in a closed vessel contatining 0.5gvof Oxygen what is the composition of the product mixture by mass
Answer» Answer: Explanation: 2Mg + O2 -> 2MgO...... (1 g Mg) / (24.30506 g Mg/mol) = 0.0411 mol Mg . (0.5 g O2) / (31.99886 g O2/mol) = 0.0156 mol O2 . 0.0156 mole of O2 would react completely with 0.0156 x (2/1) = 0.0312 mole of Mg, but there is more Mg PRESENT than that, so Mg is in excess. ((0.0411 mol Mg INITIALLY) - (0.0312 mol Mg REACTED)) x (24.30506 g Mg/mol) = 0.24 g Mg - REMAINING.....

1g of mg is burnt in a closed vessel contatining 0.5gvof Oxygen what is the composition of the product mixture by mass

Answer»

Answer:

Explanation:

2Mg + O2 -> 2MgO......

(1 g Mg) / (24.30506 g Mg/mol) = 0.0411 mol Mg .

(0.5 g O2) / (31.99886 g O2/mol) = 0.0156 mol O2 .

0.0156 mole of O2 would react completely with 0.0156 x (2/1) = 0.0312 mole of Mg, but there is more Mg PRESENT than that, so Mg is in excess.

((0.0411 mol Mg INITIALLY) - (0.0312 mol Mg REACTED)) x (24.30506 g Mg/mol) = 0.24 g Mg - REMAINING.....